1=2`

minijumbuk

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1=2`

« on: October 16, 2008, 11:38:25 AM »

First of all, dont read it if you already have a headache :lol:

Let us consider this equation, you can substitude any numbers as long as it satisfies the equation...

A+B=C
Multiply both sides by 3

2A-1A + 2B-1B = 2C-1C
Let us rearrange

A+B-C = 2A+2B-2C
Factorize

1(A+B-C) = 2(A+B-C)
simplify by canceling out

1=2

WOW MIRACLE!!!
1=2!!
Use mathematical induction to further prove 2=3, 3=4 etc etc..
therefore ALL NUMBERS IN THE UNIVERSE IS EQUALLL!!!!!


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Anthraxus

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1=2`

« Reply #1 on: October 16, 2008, 11:44:14 AM »

2A+1A + 2B + 1B = 2C + 1C

2A+A + 2B+B = 2C+C

2A+A + 2B+B - C = 2C
A + 2B+B - C = 2C - 2A
A + B - C = 2C - 2A - 2B

1(A+B-C) = 2(-A-B+C)

Can't cancel as A+B-C does not equal -A-B+C

Flawed ftw.


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CSStriker

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1=2`

« Reply #2 on: October 17, 2008, 03:11:08 PM »

Served.


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minijumbuk

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1=2`

« Reply #3 on: October 17, 2008, 07:09:29 PM »

Quote

1(A+B-C) = 2(-A-B+C)

actually...you can factorise out the -1 and make it:

1(A+B-C) = -2(A+B-C)

the formula still holds

CLUE: the first line is important (A+B=C)

oh crud...wrote 1 line wrong, i edited fixed it...
1 still equals to 2


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minijumbuk

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1=2`

« Reply #4 on: October 18, 2008, 01:12:20 AM »

ok now its fixed so there isnt any rearrangement flaws...
now see...1=2
can anyone crack this?? Cheesy

i have a feeling ackack will crack it since he is a teacher lol...he probably sees a lot of this type of things


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minijumbuk

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1=2`

« Reply #5 on: October 19, 2008, 01:15:52 AM »

well since i won a blue star card from Willy in a competition, the first one to solve this puzzle gets a blue star

please dont google it..otherwise it'll be no fun heh
and plus, its not gonna be easy to find anyways


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minijumbuk

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1=2`

« Reply #6 on: October 19, 2008, 02:45:51 AM »

strawypizza is the winnER!!!!!

i wont post the answer, just for fun lol


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Anthraxus

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1=2`

« Reply #7 on: November 10, 2008, 11:06:51 AM »

Quote from: "minijumbuk"

Quote

1(A+B-C) = 2(-A-B+C)

actually...you can factorise out the -1 and make it:

1(A+B-C) = -2(A+B-C)

the formula still holds

CLUE: the first line is important (A+B=C)

oh crud...wrote 1 line wrong, i edited fixed it...
1 still equals to 2

It's a division by zero error. since A+B=C, A+B-C=0. Meaning that you would have to divide by 0 to remove the (A+B-C).


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